ploat a hyperbola

[Darin.K]

My bad, forgot to save with the default values properly set.  Since I assumed you were ultimately looking to do a little more than plot that specific hyperbola, I gave you a general formula with parameters.

[Ben]

---

Alain S wrote:

...

EDIT: Altenbach is better in LV programming and faster in typing than me

...

---

That is a truism that warrents promotion to the LV Proverbs thread.

Ben

[Darin.K · Accepted solution]

I have forgotten quite a bit about conic sections, but I still know my latus rectum from a hole in the ground.  The points you called A and B are the foci, let's assume they are symmetricly placed on the x axis A=(-f,0) B = (f,0).  The number '3' you used is the length of the transverse axis (minimum distance between the two sections), I'll call that C.  You can convert this to the form I used ax^2 - by^2 = 1 with the following equations: a = (2/C)^2, b = 1/(f^2 - a^2).  The attached vi lets you enter the focal distance (f) and the transverse axis length (C). 

[altenbach]

---

Alain S wrote:

EDIT: Altenbach is better in LV programming and faster in typing than me

---

OTOH, it would not hurt to be faster in programming and better in typing. 😄

[Kolos]

Huh man! Thanks!

Can i somehow plot my A and B point in the same graph?( (-f,0) and (f,0) )

[altenbach]

Yes, create a second plot for your xy graph that only contains these two points and has a point style.

[Kolos]

I can't do it... 

[altenbach]

Maybe something like this?   Modify as needed....

Message Edited by altenbach on 07-27-2009 09:16 AM