Finding consecutive repeating numbers in binary array (or boolean)

[altenbach]

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@simmertime wrote:

The input is a digital waveform of size 496 (1D).

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A digital waveform can have several signals. Can you give a more specific example? Are you using the tools from the digital conversion palette? (would give a 2D boolean array or a numeric array with multiple bits/value).

My code above can easily do exactly what you need.

• output the number of TRUEs if there is exactly one consecutive stretch of TRUEs (Count: 1..N)
• output 0 if no TRUE exists. (same as "none found")
• output -1 of more than one group of TRUEs exist. (same as "error")

[JÞB]

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@simmertime wrote:

The input is a digital waveform of size 496 (1D). I convert it to a boolean array(T/F) and binary array(0/1) for other reasons. From the input I want to count how many ones are sandwiched between zeros, but if there are more than 1 sandwich I want to have a string indicator that there is an error. If there are no 1's found, I would like the string indicator to say none found. 

000111111000 Count= 6

0001110000111100 "Error"

000000000000 "None found" 

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There are a few more cases to define.

1111100000 or 0000011111 no leading / trailing 0 1s length indeterminate?

0000111111100111 or 1100001111110000 one sandwich and an incomplete pattern?

[simmertime]

If a 1 is at the start or the end that is an error. I would call it "incomplete data" regardless if it is 1110000 or 11000111000 (doesn't matter if it is the only chunk)

[simmertime]

Can you include this vi or list the components used? I'm having a hard time identifying them. 

[altenbach]

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@simmertime wrote:

Can you include this vi or list the components used? I'm having a hard time identifying them. 

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This is a long thread. Are you replying to any particular message? In that case you should quote some of it (as I just did right here above) so we know what you are referring to.

[altenbach · Accepted solution]

Here's my VI from the picture above. You might have trouble finding the "search array" because it has changed to a malleable tool (different color, more functionality)  in recent versions.

[altenbach]

To wrap this up, here's how it can be simplified if we only want the simple nonzero count and -1 otherwise.

(You can add the "OR Sum=0" back if you want to output zero if the array is all FALSE)

- Output the count of TRUEs if there is exactly one consecutive stretch flanked by FALSE
- Output -1 if
     - There is more than one stretch of TRUEs
     - All elements are FALSE
     - The input starts or ends with a TRUE

[simmertime]

Hi altenbach,

I liked that the output could be -1 (invalid), 0 (no 1's found), or the sum. I added a few things to search if 1 is found in the beginning and the end and output an error (just an index array for the first and last, then OR those together). Thanks for your help!