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Arithmetic mean

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Hello!

 

Does anyone have the OpenG Arithmetic Mean VI (at least the one for 2D array). I have installed the OpenG Numeric package, but cant find it there.

 

Or maybe even better, does anyone have a VI or a good solution for calculating the mean of columns in a 2D array?

 

Greetings

Kristoffer

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Mensaje 1 de 20
7.105 Vistas

CM.png

 

does this Help?


"Should be" isn't "Is" -Jay
Mensaje 2 de 20
7.098 Vistas

Thank you!:)

 

Just a further question: Is there any possibility for also using a time column when calculating the mean? Such that the code take into account the length of the samples as well (given that the sample time is not a fixed value).

 

Greetings

Kristoffer

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Mensaje 3 de 20
7.062 Vistas

There are no native functions that I am aware of (not saying it does not exist).

 

How are your time samples taken? 

ie:  seconds since last sample..?

timestamp?

 

For instance, if it is a timestamp, and they are in an array, you can take the difference from the previous element, and then calculate the mean.

Mensaje 4 de 20
7.050 Vistas

As it is now it is an array of type string, but I am trying to convert the type of the whole array into timestamp. I was then thinking of doing just as you say, taking the difference from the previous element. Do you have any good examples of a loop where this is done?:)

 

Greetings

Kristoffer

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Mensaje 5 de 20
7.035 Vistas

This will do if the timestamp string is local specific

scan.png

 

If your timestamp string is in a different format

Here is a link to the Formats you would use

E.G. %<%Y/%M/%d %I:%M:%S %p>T  would create a timestamp from "2012/04/10 2:04:51 PM"


"Should be" isn't "Is" -Jay
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Mensaje 6 de 20
7.009 Vistas

Broken Link-  Don't know what happened

 

Here


"Should be" isn't "Is" -Jay
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Mensaje 7 de 20
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Hello!

 

I have transformed the 2D array from string to timestamp! I was more thinking of a good structure for taking the difference from the previous element when the array is of type timestamp.

 

Greetings

Kristoffer

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Mensaje 8 de 20
6.977 Vistas

nothing simpler

aa.png

 


"Should be" isn't "Is" -Jay
Mensaje 9 de 20
6.971 Vistas

Thanks again. But, that will be for a 1D array if I'm not wrong? My array is a 2D, so i guess i'll need to either add a loop for iterating both columns and rows or something?

 

Greetings

Kristoffer

Mensaje 10 de 20
6.967 Vistas