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Arithmetic mean

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Bingo- just wrap another loop in there


"Should be" isn't "Is" -Jay
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Message 11 of 20
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Seems like it worrked now. Thank you very much for the help!:D

 

I have attached a picture of what I have done, does it seems correct to you as well? I was trying to use the "Build array" together with a "0" constant, but then the resulting array was a appended array of 3D. Also, some of my columns are of different size (different number of elements). However, it doesn't seems like this code is taking that into account.

 

Greetings

Kristoffer

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Message 12 of 20
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@Jeff Bohrer wrote:

nothing simpler

aa.png

 



Maybe a little simpler...

 

TimeInterval.png

Message 13 of 20
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I think that the structure works pretty good, i only need to get rid of those extra elements and i consider myself done. Any suggestions to that?

 

In the dataset column 0 might have 53 elements while column 1 has 52 and column 2 has 54. The code does not seem to care about this, because all columns have the same amount of elements. Any suggestion why this happens?

 

Greetings

Kristoffer

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Message 14 of 20
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@Darin.K wrote:

@Jeff Bohrer wrote:

nothing simpler

aa.png

 



Maybe a little simpler...

 

TimeInterval.png


I guess I'll make the Rube-Goldberg Thread after all!!! Smiley Very Happy


"Should be" isn't "Is" -Jay
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Message 15 of 20
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@Sjefsgjogleren wrote:

I think that the structure works pretty good, i only need to get rid of those extra elements and i consider myself done. Any suggestions to that?

 

In the dataset column 0 might have 53 elements while column 1 has 52 and column 2 has 54. The code does not seem to care about this, because all columns have the same amount of elements. Any suggestion why this happens?

 

Greetings

Kristoffer


LabVIEW forces rectangular arrays.  No way around it.


"Should be" isn't "Is" -Jay
Message 16 of 20
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So i cant remove those elements later og anything? Because I am not quite sure where the values that it puts inside actually comes from either. I guess that there is just some default values (seems to be 5 and 10). Or maybe I can get the actual length of the column and only use that amount of datapoint for the later calculations?

 

Greetings

Kristoffer

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Message 17 of 20
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@Sjefsgjogleren wrote:

 

I have attached a picture of what I have done,


Missing picture.

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Message 18 of 20
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Ooops, forgot!

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Message 19 of 20
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Solution
Accepted by Sjefsgjogleren

If you simply pull down on the index display of the constant in my last snippet to create a 2D array of timestamp, and make the output a 2D array you are all set.

 

TimeInterval2.png

Message 20 of 20
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