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selected with rectangular

Hi all

I wanted to select part of my image with rectangular and I like to see exactly this part  in another Intensity graph, I use this code that I attached but when I selected some part , I see another part in different coordinate.how can I see the exactly part that I selected?

 

Thanks for your help

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Message 1 of 14
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I don't undertsnad your question, can you repeat it, this time more clearly and in a structured manner?

 

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Message 2 of 14
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In my code, I select a part of image to show in region of interest(Intensity Graph 2), but instead of selected part (using rectangular shape ), non related part appears in my region of interest window (Intensity Graph 2).

 

Regards

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Message 3 of 14
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Did you select the part you want through Clamp function? I couldn't open you Vi as my LabVIEW version is different to yours. Are the below links useful?

 

http://digital.ni.com/public.nsf/allkb/82C6023BCC87F5CA86256F38006D2C98#Q5

 

http://digital.ni.com/public.nsf/allkb/82C6023BCC87F5CA86256F38006D2C98#Q6

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Message 4 of 14
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No, I did not use Clamp function.

I use the Plot Images to put a rectangular overlay on the Intensity Graph.

I attached the pictures of my code.

 

Regards

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Message 5 of 14
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Did you read the links I send over? Or were they not useful?

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Message 6 of 14
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Thanks,I saw this links before but they were not useful for my aim.

I use Intensity Graph and that has not some cursor like Image display (if you see in Image display, you can see some cursor like rectangular selection) then I need definition rectangular selection first but I can not controll the coordinate of my rectangular.

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Message 7 of 14
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Does the Intensity Graph have a "coords to XY" property? Perhaps get an array subset of the data bounded by the coordinates.

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Message 8 of 14
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The Intensity Graph have some property like "curser XY".I use one example for my code that in this example used for "Plot Bounds" property and it shows me some minus valuse! I want to find reletive between my rectangular coordinate and this numbers.

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Message 9 of 14
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I was thinking of the data itself. This is messy code, and my LV2012 is down, at the moment, so I can only see your jpgs above, but this is what I was thinking:

IntensitySubset.png

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Message 10 of 14
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