regular exp

[tinnitus]

Hello,

i have a string buffer like this  \s\sNN.NN\s\s\s\sNN.NN\s\n

where NN.NN is value is measurement is OK  , could be open is not present

I would like to extract this two NN.NN  with regexp

an idea ?

Regards

Tinnitus

[Ray.R]

You could use the scan from string function:

 

[Ray.R]

I know I should not assume that you would want the values to be converted to doubles.

Here's a link to the regular expressions thread, which may be useful:

http://forums.ni.com/t5/BreakPoint/Regular-Expressions-Board/td-p/1187799

[Ray.R]

I have to run to a meeting, but here is a quick reg expression.  You'll need to fix it to get 2 significant digits:

 

[jcarmody]

This VERY SLIGHT modification gets you all the digits past the decimal point.  You can replace the asterisk with {n} to specify exactly how many digits you want.

[jcarmody]

With one MRE (assumes only spaces separate the numbers):

[ben64]

You can simplify the regex to "\S+", one or more character that is not a space if the output is always of the type \s\sNN.NN\s\s\s\sNN.NN\s\n.

Ben64

[ben64]

Alternate regex

Ben64

[Darin.K]

In terms of flexibility and syntax error catching, I tend to prefer to use the digit class (\d).  Let me just remind the regexers about negative numbers. 

If spaces are the enemy, then Ray.R chose the correct function but wandered into RG territory when he thought strings would be the desired output.  Just let Scan From String do its voodoo.

[Ray.R]

We still don't know if the OP wants doubles or strings or why use regular expression at all.  I decided to go the regEx example because that was what was asked.. 

Thanks Jim for the simplified examples.  I enjoy learning more regEx.

I prefer the Scan from String as it does the trick..  and it can convert to the appropriate type in one shot.  🙂