how to call subvi Asynchronously with version 8.6

[bozeman]

With new version 2011, labview has a function of Start Asynchronous Call, but version 8.6 does not have it.

I would like to call subvi, but not waiting for subvi to finish before excute the next step in main vi.   

An asynchronous call to a subVI starts execution of the subVI while allowing data flow to continue in the calling VI.

Anybody can help on how to realize this in version  8.6.

Thanks

[altenbach]

You simply need to call it dynamically the old fashioned way:

Open a VI reference and run it using the run VI method. Make "wait until done" false.

[bozeman]

Thanks for helpl. I am still very confused about this. how to open that run vi method? 

can you give me a simple example including Open VI Reference Function, call reference by node and this run vi method.

Thanks

Yihan

[Ben]

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@bozeman wrote:

Thanks for helpl. I am still very confused about this. how to open that run vi method? 

can you give me a simple example including Open VI Reference Function, call reference by node and this run vi method.

Thanks

Yihan

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THe code for this Nugget should serve as an example.

Ben

[bozeman]

Hi Ben,

I attached one sub vi and one main vi here.  It is very simple example.

I want to main vi stops before subvi. But it does not work. Can you take a look?

If I remove the run vi session, just connect the open vi reference to call reference node, it works. The problem is when I inserting the run vi method in between, something is wrong.

yihan

[Ben]

Did you look at the example I offered?

I typically don't look at posted VIs (my public machine has LV 7.1 and earlier) but I will look at jpgs.

Ben

[JÞB · Accepted solution]

make case 0 look like this

[bozeman]

works!!!!

thanks so much.

one more question, after Open VI Reference Function , i need to link type specifier vi refnum,  I was tyring to creat a constant from type specifier vi refnum terminal , and then select the subvi , but it does not work. I did your way, just simply link the Static VI Reference Function to type specifier vi refnum, then it works. Can you explian it? Thanks again!!!!

big help!!!!