derivative problem

[Ezzow]

I tried to figure it out with a shift register and it also worked perfectely. Thank you so much @CARYA 😊 

[altenbach · Accepted solution]

Since you are not interested in absolute times, (just time differences), I would substitute "high resolution relative seconds" (Simpler datatypes, no coercion dots, etc.) and a feedback node.

Note that you get a division by zero on the first iteration (that possibility exists even in your code!). You can program your way around thus but since you don't even initialize the upper shift register, it seems you don't really care.

(Of course since you do single point acquisition, you should probably run the loop at a defined loop rate. Then you don't even need to measure dt because you already know it.)

[Ezzow]

@altenbach 

I really apreciate your help. I tried it with "high resolution relative seconds" and it worked properly 😉

(Of course since you do single point acquisition, you should probably run the loop at a defined loop rate. Then you don't even need to measure dt because you already know it.)

Do you mean by using a wait function? 

[altenbach]

---

@Ezzow wrote:

@altenbach 

Do you mean by using a wait function? 

---

Yes. Just make sure it is the determining factor, i.e. it is the slowest part of all loop code.