Simulate a Current waveform

[LeoLiu]

for u said"To see the current of this signal it will be down to you using formulae to extract it from a power waveform."

Could you explain this or just making a simple vi to show me , i will great appreciate that, thank you!

[NIquist]

You're not confusing LabVIEW with circuit simulator software are you?  In order for current to flow there needs to be some kind of load for it to flow through.  A simulated sine wave doesn't have a path for current to flow so your request is confusing.  You could use math functions to pretend there is a load.  Just divide the sine wave by your resistance and plot the result. 

[LeoLiu]

Cool man!!!

Tell me tell me !!  i really want to know

im not quite know how to use labview

so could you show me how to use math to pretend a load?

just build based on my vi , i will great appreciate that!

[NIquist]

Here is a simple way to do it.  It is just showing the current based on ohms law (I=E/R).  This doesn't take any phase shift into consideration but it should do if you're just playing with simulations for now.

[JohnMc19]

Hi LeoLui,

If you are still learning in LabVIEW then it would be beneficial to look through our tutorials or try the examples that are already in your LabVIEW package!

Find examples from the 'Help' tab on the top of any LabVIEW window.

Regards,

[LeoLiu]

That's cool, man, it is what i want.

btw, if i want add a phase shift, how to do that?

[NIquist · Accepted solution]

Well, unfortunately you're using dynamic data instead of real waveforms so there's no way to change the timing (I'm not really sure on that since I never use dynamic data, Express VIs or DAQ Assistant).  If it was waveform data types you could just change t0 with the Set Waveform Components VI.  You would have to know how much to phase shift of course.   That would depend on your hardware, cabling, load type, etc.

I would just save all that until you learn LabVIEW better and are ready to tackle the real-world signals.