How to generate a string with a known length with a particular character.

[msabah38]

I have a string take for example : labview , I would like to convert it into a string with look like this: ******* . 

My logic should be like, first find the string length, and then replace the character with *. 

Can anyone tell which blocks I should use to make this possible.

[kartiknattar]

Are you trying to replace the strings or you want to display the string as password??

If you want to display the string (control/indicator) as password you can try below method by just right click.

 

[thols]

These are quite rudimentary operations. Browse the string functions and see what you find. It is all there. Have you taken any courses? The forum board lists training resources to get you started.

(I am also curious if you really just wanted to set the string to password display)

[santo_13 · Accepted solution]

These are two techniques I would use

[altenbach · Accepted solution]

I agree with some of the other posters that you are probably looking in the wrong place for a solution. can you explain in more detail what you are actually trying to do?

In any case, here's one possible solution (string size, for loop, indexing tunnel, concatenate strings):

[RTSLVU]

Here's another way...

But like the others I wonder why you would need to do this...

[altenbach]

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@RTSLVU wrote:

Here's another way...

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You need LabVIEW 2021 to do it this way. 😄

[RTSLVU]

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@altenbach wrote:

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@RTSLVU wrote:

Here's another way...

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You need LabVIEW 2021 to do it this way. 😄

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This was feature released in LabVIEW 2012

https://forums.ni.com/t5/LabVIEW-Idea-Exchange/Add-a-quot-Concatenate-Indexing-quot-option-for-array...

[aeastet]

I think he was giving you a hard time because you posted it using LabVIEW 2021. Not that what you did was not available before that. 😁

[paul_cardinale]