How to access only the third dimension within a 3d array?

[RavensFan]

It looks like a good start.

Remember what I said about For Loops.  The iteration counter begins at 0.  But your loops start at either 1 (for n loop) or 2 (for i and j loops).  So you need to add 1 or 2 to your iteration value before you do anything else.

From here on, you'll just have to add more code to account for the other parts of your equation.

[sbash123]

thank you, i completed that section. and now need to set the boundary conditions because as i run the code i encounter the error that labvoew has run out of memory, so again using index array and replace array subset in the first loop i have to carry out this code. how could i equate them? 

u(1,:,n+1) = u(2,:,n+1) ;
u(length(x),:,n+1) = u(ni-1,:,n+1) ;
u(:,1,n+1) = -u(:,2,n+1) ;
u(:,length(y),n+1) = -u(:,nj-1,n+1) ;

kindest Regards,

[RavensFan]

I don't know what you mean by "set the boundary conditions".

[sbash123]

i want to set a maximum limit for the arrays when they execute, as my code stand it doenst run because there isnt enough memory in labview. 

[johnsold]

See the boundary condition question in this thread.

Lynn