Clear shift register before running VI again

[Gear]

I have this very simple VI that read voltage from a DAQ until I stop the loop, it then saves the data into a .wav file.

My problem is: everytime I stop the VI, I would expect the shift register to clear. But if I restart the VI it saves the old data from the shift register and the new data into the .wav file. I just want the new data when I run the .VI, without having to close the program everytime.

Please help.

[Ben]

Pop-up on the SR and create a constant.

Ben

[Gear]

Hi, I tried doing that with a zero constant, but it causes a bunch of broken wires since the wire type is dynamic, but the constant is not.

[Ben]

We I'll be... !

I never use the dynamic data type so  I can only offer a possible work-around.

Cntrl-copy the the Waveform Graph 2.

Right-click and select "Change to Constant"

Wire that newly created constant to the outside of the SR.

Does that work?

Ben

[Gear]

That allows me to create a constant(a very weird looking one), but it does not clear the shift register.

[Ben · Accepted solution]

right click the array control and choose "clear array" (or whatever tht option os called) and try it again. that is a cluster of an array of waveform data types. You can right-click (afterwards) and choose "view as icon".

Ben

[garrettmarsh · Accepted solution]

When you use that method to create a constant, it keeps the data from the control that it originated from.

Right click on the edge of the array constant until you see an option that says "Data Operations" > "Empty Array".

That should clear it out.

EDIT: oops, Ben posted the same thing while I was typing.

[LCI_RnD]

You need to initialize the shift register. The best way I've found to do that with dynamic data is to use a conversion to a blank array constant. See the attached screen capture

[Gear]

Perfect!! But the name was "delete element"! Great idea with the "replace" option!!

[Gear]

Perfect!! But the name was "delete element"! Thank you