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Average Value Scope

Doing something manually has absolutely nothing to do with code or for loops or timeouts. I don't see why you don't understand what you've been told to do. Just walk away from your computer.
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Message 21 of 46
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Yes ı made it sir .

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Message 22 of 46
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What time base (seconds/division) are you using?


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"Not that we are sufficient in ourselves to claim anything as coming from us, but our sufficiency is from God" - 2 Corinthians 3:5
Message 23 of 46
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What is time base sir . Can ı understand in attachment ?

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Message 24 of 46
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@ELEPRO wrote:

What is time base sir .


In all seriousness, if you do not understand what I mean by time base, you need to go find a professor and have them teach you how to use an oscilloscope.

 

Time base is the number of seconds per division in the horizontal axis.  It looks like you are using 500ms/division.  Since there are 10 divisions on the screen, you are capturing 5 seconds worth of data per trigger.  So in order to capture 512 waveforms to average, you will be waiting at least 42 minutes.  Since it looks like the interesting part of your waveform is 4 divisions (2 seconds), you could decrease your time base to 200ms.

 

Since you are also going for an average waveform, you should not use an auto trigger.  A trigger level of 0.5V on a rising edge should work well for you.


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Message 25 of 46
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Thank you so much sir.

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Message 26 of 46
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Hello sir ,

 

I made exactly what you say. I configure  #Average 512  in my scope and ı see the signal in my scope .  But when ı  run same vi, again vi is not working and says "VISA:  (Hex 0xBFFF0015) Timeout expired before operation completed." 

 

1232.PNG

 

AND eror :

 

oo.PNG

 

 

What should ı do ?

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Message 27 of 46
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2ms/div*10div = 20ms of data per cycle.  Multiply that by 512 cycles needed for the average and we get ~10.25 seconds.  I'm willing to bet that your VISA timeout is set to 10 seconds.  So of course you are going to get a timeout.  And that is not counting the time between the signal pulses.  How often are those singnals sent?

 

In short, you need to add delays to your code in order to allow for the signals to be fully captured before you can get them.


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Message 28 of 46
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When ı looked the quick drop. I didn't find delay. What should ı  do sir ?

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Message 29 of 46
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@ELEPRO wrote:

When ı looked the quick drop. I didn't find delay. What should ı  do sir ?


Take some tutorials.  The Wait (ms) is one of the most important functions when dealing with instruments.

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"Not that we are sufficient in ourselves to claim anything as coming from us, but our sufficiency is from God" - 2 Corinthians 3:5
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Message 30 of 46
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