Array of clusters

[-Chris-]

Hello,

I would like to obtain an array of clusters of two elements (x,y). The user should be able to choose ending values (ev) of the elements, and the starting value (sv) is always equal to one E.g.:


1. (sv=1, ev=2) gives in the result: (1,1) (1,2) (2,1) (2,2)

2. (sv=1, ev=3)

(1,1) (1,2) (1,3) (2,1) (2,2) (2,3) (3,1) (3,2) (3,3)

3. (sv=1, ev=4)

(1,1) (1,2) (1,3) (1,4) (2,1) (2,2) (2,3) (2,4) (3,1) (3,2) (3,3) (3,4) (4,1) (4,2) (4,3) (4,4)

3. (sv=1, ev=4)

(1,1) (1,2) (1,3) (1,4) (2,1) (2,2) (2,3) (2,4) (3,1) (3,2) (3,3) (3,4) (4,1) (4,2) (4,3) (4,4)


4. and so on…

I am working with LabVIEW 8.6. Any help appreciated.

Thanks!

[Ben]

What you ae asking for is trivial using a pair of nested For loops a shift register and a build array node.

Investigate those functions and post images of your code if you get stuck.

Ben

[-Chris-]

Yes, I believe that this is trivial but I am fairly new to LabVIEW. Where should I put the shift register?

[Ben]

on the outer For loop. It will acumulate your work as you go.

Post images if you want better help.

Ben

[-Chris-]

I have something like this and it works, but think there might be a better solution.

[Ben]

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@johnnypp wrote:

I have something like this and it works, but think there might be a better solution.

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What a difference an image makes!

That is better than what I had in mind if you are OK with the 2D array. If you want it to be 1D you can reshape (see array palette) the results to 1-d.

Ben

[-Chris-]

Thanks Ben!

[Yamaeda]

Just change the constant 4 to a Control wired to both N's and you've solved the user input question. 🙂

/Y