niVB_Dig_Initialize

[eamonndoe]

I want to configure the DIO pins 0, 1, 3 & 7 as outputs, 6 as an input. How can this be accomplished using niVB_Dig_Initialize in the C API?

The colon syntax doesn't work.

I read in the forums[1] that I should be able to pass "vb/dig/0,dig/1,dig/2,dig/7" to niVB_Dig_Initialize. That however fails with an error code indicating that the syntax is wrong. I can in fact pass this syntax to niVB_Dig_Write but not niVB_Dig_Initialize.

What am I doing wrong?

[1] https://forums.ni.com/t5/VirtualBench/Can-VirtualBench-be-programmed-in-C-Or-anything-other-than-LV/...

[DLarsen]

eamonndoe,

It looks like you're specifying 'vb/dig/0' for the first but then 'dig/1', etc for the other channels you want to initialize.  I believe you're allowed to use either, but not mix the two. (So I believe you should change to 'dig/0,dig/1,dig/2,dig/7' or 'vb/dig/0,vb/dig/1,vb/dig/2,vb/dig/7').

----------------------------------------------------

Daniel Larsen

Digital Hardware Engineer

National Instruments

[eamonndoe]

Thanks for the response Daniel.

Just to be clear, when I say "vb", the default is model-serial, so the actual string that I'm successfully passing to niVB_Dig_Write() is: "VB8012-1234567/dig/0,dig/1,dig/7". This seems to be in line with what I see elsewhere but I can certainly try "VB8012-1234567/dig/0,VB8012-1234567/dig/1,VB8012-1234567/dig/7" if that's what you're suggesting? Doesn't seem right but I'll try it when I get to my desk.

Thanks.

[eamonndoe]

Much to my great surprise, that worked! Many thanks for your timely response.

Alas I have already hit the next snag so I predict that I'll be back.

[eamonndoe]

So here's the other issue I see:

Having configured pin 6 as an output, we drive it high. We then need to use that same pin as an input. What we see is that the line is held high, even after we have called niVB_Dig_Close and then niVB_Dig_Initialize so that pin 6 is now configured an input.

What do I have to do to reconfigure a pin as an input after it has been used as an output?