string to 2D string array conversion

[Kals]

Hi,

I have a string like this below. I would like to extract all the texts within the quotes "  ". How to do that?.

05-Mar.20:52   skalyana    label type "BASELINE_1.2" (locked)
28-Apr.19:19   skalyana    label type "BASELINE_1.8"

i have tried using Match regular expression. I am able to extract one text within " ".

I would like to know how to extract all the text within " "

I have attached the vi for your reference

Thanks

Kalyan

[jcarmody]

Use a While Loop with a Shift Register to keep looking until you've found them all.

[Kals]

Hi,

    Thanks for the solution. One more clarification. I would like to remove the character " from the output.

Example like this

BASELINE_1.2

BASELINE_1.8

How to do that?

Thanks

Kalyan

[jcarmody]

With a submatch, notice the parentheses and the new output (Match Pattern is expandable).

[Kals]

Hi,

   I would like to extract the text between the character ( ) also.

 for example here locked (locked)

Thanks

Kalyan

[jcarmody]

I don't see parentheses in your sample data.  Do you want what's in quotes AND parentheses or are you confused about the parentheses I've added?

[Kals]

Hi,

05-Mar.20:52   skalyana    label type "BASELINE_1.2" (locked)
28-Apr.19:19   skalyana    label type "BASELINE_1.8"

I need both the text within " " and within ( ) from the above sample.

Thanks

Kalyan

[jcarmody]

Sorry, I missed seeing (locked) in your original data.  This doesn't return them in order.  Is that important?

[moderator1983]

Hi Jim,

its simply superb...

how to get more info on these 'Regular Expressions', is there any KB (knowledge base) or tutorial available for the same.

[jcarmody]

---

@moderator1983 wrote:

how to get more info on these 'Regular Expressions', is there any KB (knowledge base) or tutorial available for the same.

---

Click on the "regex" link in my signature; it's my favorite.  Darin.K contributed this cool tool to the Community; it's worth downloading and playing with.