stop a VI if it does not give a value or it exceeds a certain time

[ziedhosni]

Hello,

I would like to stop a running vi if a timer exceeds a certain time. I am running a calculation but sometimes it takes ages to finish so, I would like to programmaticaly stop its VI if let's say run over 1min without giving a result and stopping by itself.

I tried the elapsed time with the while loop but it is not working as I have a control&simulation loop inside the while loop and it is stucked there (slow integration) which prohibits the while loop to stop if the maximum run time is reached.

Thanks,

Zied

[RTSLVU · Accepted solution]

Maybe you could modify this VI to suit your needs.

[ziedhosni]

I have all the time a specific vi that I want to stop . I notice that the order of the VIs in memory can change and I have to select manually the right name.

So, I put as constante the VI reference. Unfortunately, I t did not stop the VI and I got error 1004.

I attached the modified VI.

[udka]

Can you try replacing the spaces in vi name with maybe "_" or some other but without spaces?

Make sure the vi is open before executing this.

Ref:http://digital.ni.com/public.nsf/allkb/96143643917AF5E6862570D90081152B?OpenDocument

[RTSLVU]

Try this:

[ziedhosni]

This last method worked for me but when I use the VI as a subvi I get error 1000 and the main VI gives the following error:

Error 1000 occurred at Invoke Node in formula (SubVI).vi->core algorithm v11.vi

Possible reason(s):

LabVIEW:  The VI is not in a state compatible with this operation.

Method Name: Abort VI

[RTSLVU]

Then don't make it a sub-vi.

I would just put something like this right on the top level VI block diagram and have it run independently of the main program.