replace array column by row definition

[FredFred]

Hello to all,

I have an initialized 2D 10x10 array with all values being zero.

How can I insert a 1D array into any of the 10 columns starting at any specified row?

The 1D array will never exceed the 10x10 parameter

Thanks N Advance!

FredFred

[FredFred]

The only way that I though to do this was by using a for loop and inserting the values into the array one by one...

Is there a simpler way to do this?

Thanks!

[altenbach]

You have to use a loop, however, you can still simplify your code quite a bit.

Use autoindexing! (This will eliminate the array size node and the index node inside the loop). 🙂

See attached, LabVIEW 7.1.

[Darren]

When I first saw this question I thought you had to use a loop too, but my boss and I talked about it for a minute and he came up with a way to do it without a loop, but instead with two Replace Array Subset functions.  Check it out:

I've also attached the VI, saved in 8.0 format.

-D

Message Edited by Darren on 03-20-200603:16 PM

[FredFred]

Thanks

altenbach 

I've always had a problem with auto indexing, but now realize its value. Thanks a bunch

[altenbach]

Darren,

Cute! I was always a sucker for "loop free" algorithms! 🙂

In this case, the loop version is probably a bit more efficient and the code size is actually ~20% smaller (2K vs 2.4K).

For a 10x10 array it does not really matter. For huge arrays, only a benchmark will tell. 😉