problem with while loop ( without delay)!

[ha noi]

I want to make a main VI, that calls some control value from 2 different VI ( position.vi  and value.vi ). I put 100 ms delay in position.vi , and 1000 ms delay in value.vi. But in the main VI, i don't want to put any delay. So I got problem with main VI , it works seem not correct!  How can i fixed it? Thx.

The working way of main VI ( try123.vi)  same with the ideal.vi ( attached).

[ha noi]

The ideal.vi

[MikeS81]

Hi ha noi,

i attached an example of what i mean in the other thread. It is not yet ready, but you can think about it i tell me if it can be a way to solve your problem.

Mike

[ha noi]

Thanks mike!

I'm trying to understand your vi. You can try my vi, then you know how it works! I just want to delete the delay! but it not work!

[MikeS81]

hello ha noi

the other Value you get from the read_value.vi is only to see if it is a new value, right?

Mike

Message Edited by MikeS81 on 01-16-2008 07:51 AM

[ha noi]

Do you mean "#" value? It's number of loop  in read_value.vi ( 1 loop => 1 value created).

[MikeS81]

hi again,

i think this vi now do what you want.

Mike

[ha noi]

I tried to run your vi, but it not works in my computer.

I have a question for my vi : i thought the second case structure not works. But the position indicator worked ( it showed the changing of position) so i think it's work. But why the array indicator almost time is [0,0] ?

[MikeS81]

Hi

now it works. The values are captured by the queue. Now you have to check the main functionalty of that what you want.

Mike

[ha noi]

It's work!  Can you explain the reason that number of main loop increse not very fast? Normally, in few second it can reach more than 20.000 loops ( if i don't put any delay)! Thanks  alot!