plot a hyperbola

[Kolos]

Hi!

I wan't to plot x^2-y^2=1

How is it possibe in labview?

Thanks: Koli 

[Darin.K]

Here is a simple vi to plot ax^2 - by^2 = c.  To keep it simple I take advantage of the fact that LV won't plot NaN.  However, if you look closely you will see a small gap near y = 0.  If this bugs you, you can either increase the number of points, or change the VI to join the proper segments of the two curves.

[altenbach]

Sometimes it is easier to graph it as a parametric curve, e.g. as follows:

Message Edited by altenbach on 07-22-2009 10:07 PM

[Kolos]

Hi!

I don't understand why, but it dosent plot anything for me... 

What i need to write into the parameters?

Thanks:Kolos 

[Alain_S]

Because an error is generated ?!?

But why making it so complicated ?

You know the formula : y = sqrt (x^2 - 1)

So generate some x data and calculate corresponding y values.

Something Altenbach already showed you in another way.

So I used his vi as a start and complete it with the above formula  

I hope he doesn't mind

@ Altenbach : Can you please explain why you add two "NaN" constants into the arrays?

[dan_u]

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Alain S wrote:

@ Altenbach : Can you please explain why you add two "NaN" constants into the arrays?

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Just try it without... the plots will be connected, and that's not really what you want.

[altenbach]

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Alain S wrote:

@ Altenbach : Can you please explain why you add two "NaN" constants into the arrays?

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Well, as Dan_u already said, the NaN creates a gap in a line graph. Since you are using a graph with points, it does not matter. Try with a plot style that uses interpolation like in my example and you'll see the difference as shown below. 😉

Message Edited by altenbach on 07-23-2009 07:32 AM

[Alain_S]

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dan_u wrote:

Just try it without...

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I did ......................but there is no difference

Since the plotstyle is set to dots, no lines

Anyway thanks for the trick with the "NaN", I'll keep it in mind!

EDIT: Altenbach is better in LV programming and faster in typing than me

Message Edited by Alain S on 07-23-2009 04:34 PM

[Kolos]

hmm

I am very bad at math...

I have two point. "A" and "B". "A" is for example at (-2,0) and "B" is at (2,0) point.

I have a point called "C". I know that CA - CB = 3 . (CA means the distance between C and A). I want to plot where can C be. (it will be a hyperbola).

How can i plot it?

[altenbach]

It's also quite easy in polar coordinates because we can use complex numbers for the xy graph.

(Even simpler would be to do y=1/x switch to polar, and decrement theta by pi/4 :D)

Message Edited by altenbach on 07-23-2009 08:07 AM