how to generate 3 bit digital signal using

[amruta1]

Hi,

      I am trying to generat 3 bit digital signal using 9403 digital module and cRIO 9014.I have to generate all the combinations from 000 to 111.So i have to give boolean constant either true or false to output module 9403.I am not gettimg how to incrase step value from 000 to 001 and so on..Should i use shift register??

I know how to use shift register for integer value bt i dont hv any idae about boolean value.

     hoping for solution....

[Dennis_Knutson]

Try this simple example.

[amruta1]

                  Thank u.

                        But is it neccessary to use DAQmx ?? Is it possiple without DAQmx??becoz i hv to use digital output module in FPGA  VI...

                  And have to use generated signal in HOST VI...

[Pete.Dunc]

Yes you can do this with FPGA.  You might not need to use a shift register at all.

EDIT - You can use shift registers to store any data type if needs be

- Do you want the values to change at a given period or from a user input?

- After you ramp 0-7; do you want to stop generating, continue or set a safe state (0,0,0)?

Dennis' example is taking advantage of the fact that a number is binary.  So in the U8 - 0 is 000, 1 is 001 and so on.  As you only have 8 variables you could initialise a boolean array of all of the combinations, or you could convert the numeric to its binary equivalent to write to the 3 FPGA outputs.

For cRIO applications the CompactRIO Developers Guide shows how to communicate between Host - RT - FPGA.  You should get some more ideas from there 

[Pete.Dunc · Accepted solution]

Here is a little example which uses the Number to Boolean Array function.  The Numeric indicator has it's display formatting set to binary (%b).