Please explain how to obtain a sum of 57 here? AA 00 31 36 38 31 31 00 03 02 ZZ ZZ ZZ ZZ ZZ ZZ ZZ ZZ ZZ ZZ XX XX XX XX XX 57 (ITech website "IT6800 communication frame" manual, page 13)
Well, we would need to know what the data in the ZZ and XX actually are. But here's how you can compute it.
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