graphing partial circles

[Chod]

Hello,

I am creating a vi that graphs a circle from a certain interval, so like pi/3 to 2pi. I am using the sin and cos function. How can I graph these partial circles?

Thanks

Chod

[muks]

Can you attach your vi?

[MikeS81]

Hi Chod,

you can use an x-y-graph or you can draw the circle on a picture control.

Mike

[srikrishnaNF]

hi chod,

  Have at this attachment..

Thanks and regards,

srikrishnaNF

Message Edited by srikrishnaNF on 04-30-2010 03:21 AM

[GerdW]

Hi Chod,

when using a picture indicator you can use the DrawArc function...

[Chod]

Here is kind of what I need, although I need to be able to have a control for when to start and end the angle. I want two controls on the front panel, so when I graph it I can display any segment of the unit circle.

Thanks,

Chod

[RavensFan · Accepted solution]

Your For Loop just creates an array that has N of the same value.

Take a look at this.

Message Edited by Ravens Fan on 04-30-2010 11:08 PM

[Chod]

Awesome thank you! One more question about that. How do I start the circle at (1,0)?

[Chod]

and counter-clockwise

[RavensFan]

I just happened to go with the way you wired up the sin/cos function.  Looking at it more closely now, you had the output of sin going to X and cos to Y.  That's backwards from normal trigonometry.

Swapped the wires so that the Sine goes to the Y input and the Cosine goes to the X input, then you'll have it start at the right hand side (3 o'clock, (1,0) point) and it will go counter -clockwise.

Also, if you want to the center to be a different location, then you'll just have to add the new center point (currently 0,0) to the results of the sine and cosine function.