Urgent : Array Comparison Problem

[KLI]

Hello, I need some urgent help if possible.

I'm fairly new to Labview but I do have a certain basics.

I'm trying to accomplish the following.

I have 2 arrays of the same size.

I'm comparing the elements of the first array to a certain value.

If some of the elements fits this requirement I want the compare the corresponding elements in the second array to another value.

If the elements of this second array are indeed greater then this new value I want to switch a boolean output to yes.

EXAMPLE!

Array1 =

1 2 6

5 4 9

3 7 2

Elements of Array1 > 5 ?

x x 6

x x 9

x 7 x

Array2 =

6 4 1

6 5 7

9 8 3

I only want to use the elements at the position corresponding to the elements from array1 that were greater then 5.

All other elements can be ignored.

New Array2 =

x x 1

x x 7

x 8 x

Elements of Array2 > 6 ?

x x x

x x 7

x 8 x

If Answer = 0 : Boolean = false

In this case : Answer = 2 elements : Boolean -> True

I could really use some help.

Any idea is welcome.

Thank you in advance.

[RavensFan · Accepted solution]

I would make both array comparisons.  You'd wind up with two arrays of boolean values.  Then AND those arrays together.  Now you have an array of booleans where a True means the element in the first array met condition 1 and the same element in the second array met condition 2.

[KLI]

Nice Idea !

I will test this.

But how to know the positions in the arrays of these elements now?

[RTSLVU]

I am not sure I full understood but I threw this together really quick.

Seems to do what you wanted but it's ugly and I am sure there are better ways...

[altenbach]

There are many ways to do this.

• Do you really need to know the positions? If you just need to know of a TRUE exists in the output, do an "OR array elements". If the output is true, at least one element is true.
• Use "boolean to 0,1" followed by "add array elements". The value will tell how many elements are true.
• You could use two stacked FOR loops and build an array of the TRUE indices of the final array in a shift register.
• You could reshape the 2D array to a 1D array, use search 1D array in a loop to find all TRUEs (here is example code that could be adapted)

[RTSLVU]

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@RTSLVU wrote:

I am not sure I full understood but I threw this together really quick.

Seems to do what you wanted but it's ugly and I am sure there are better ways...

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I responded to your duplicate thread and assumed single dimension arrays, so ignore my response.

[KLI]

@ Ravens Fan : Thank You