Problem in implementing Logic

[Ranjeet_Singh]

I have a sorted array as input and output as I needed.  I need output as each element in array how much time repeated. Attached image for reference. 

I tried but didnt get what I needed. Attached VI.

[P@Anand]

Are you sure you will always have only the Alphabets in the input array?

[P@Anand]

This is little bit rubed but will help you to sort the array and count the character.

[Ranjeet_Singh]

No that will actually that will be string as each member of array

[Ranjeet_Singh]

Can you please upload in v11 

[GerdW · Accepted solution]

Hi,

here's a one loop version:

(No need to use three FOR loops…)

@Ranjeet:

In LV2011 you need to replace the conditional output tunnel by a case structure and a BuildArray inside the TRUE case combined with a shift register. See how far you get…

[Ranjeet_Singh]

Whats this?

[P@Anand]

That is conditional build terminal available in 2013.

[Ranjeet_Singh]

How can I implement in 2011

[GerdW]

Hi Ranjeet,

as said before:

You need a shift register, a case structure and a BuildArray inside the TRUE case.

Ever tried to use the example finder in LabVIEW and to study the example VIs coming with LabVIEW?