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Labview version, OS version from within a VI?

How can you determine the version of Labview running and the OS version
running (on a Windows box) from within a VI? Do you need to invoke the WIN32
API? or is there a VI component that provides this?

Any help appreciated,
Marty Burns
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> How can you determine the version of Labview running and the OS version
> running (on a Windows box) from within a VI? Do you need to invoke the WIN32
> API? or is there a VI component that provides this?
>

You can find at least part of this information from the VI server. Look
at the Application class properties.

Greg McKaskle
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Message 2 of 4
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Marty Burns wrote:
> How can you determine the version of Labview running and the OS
> version running (on a Windows box) from within a VI? Do you need to
> invoke the WIN32 API? or is there a VI component that provides this?
>
> Any help appreciated,
> Marty Burns

The VI you want is the PropertyNode vi.

Bring up your diagram and right click to get the vi palette.
Go to the 'Applicaion Control' sub-palette.
Drag a 'Property Node' vi onto your diagram.
The properties you need are:
OperatingSystem|Name "Windows Me"
OperatingSystem|Version Number and "4.90"
Application|Version Number "6.1"

Hope this helps

regards

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Works Great! Thank you very much!:)
Marty

"Dave Langstaff" wrote in message
news:1042727744.276154@dyfi...
> Marty Burns wrote:
> > How can you determine the version of Labview running and the OS
> > version running (on a Windows box) from within a VI? Do you need to
> > invoke the WIN32 API? or is there a VI component that provides this?
> >
> > Any help appreciated,
> > Marty Burns
>
> The VI you want is the PropertyNode vi.
>
> Bring up your diagram and right click to get the vi palette.
> Go to the 'Applicaion Control' sub-palette.
> Drag a 'Property Node' vi onto your diagram.
> The properties you need are:
> OperatingSystem|Name "Windows Me"
> OperatingSystem|Version Number and "4.90"
> Appli
cation|Version Number "6.1"
>
> Hope this helps
>
> regards
>
> --
> Remove "spamkill." when replying to this message
>
>
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