06-28-2023 08:38 AM
06-28-2023 08:47 AM
Use context help to find out. To turn it on, click the ? on the upper right corner of any VI. (If it looks "pushed in", it's already active.) Then hover over the node in question and you'll get your answer. For a more detailed answer, click the "Detailed help".
06-28-2023 08:58 AM
Hi bahadirozan,
it's an Unbundle function.
I guess it's from the same Anritsu manual with their bad code examples?
06-28-2023 09:19 AM
You ask a good question (to which I don't know the answer, and so far haven't figured it out, possibly because I'm using LabVIEW 2019 and this might be "something new"). But I'm frustrated by the form of your question, showing a static "picture" of a small piece of a LabVIEW Block Diagram, one that we can't "open with LabVIEW" and do what @billko suggested.
Please, when you post some LabVIEW code, do the following:
There are some clues to the "right answer" (which I thank @GerdW for enlightening me) by looking at the wires going into and out of this function. The output is clearly a 2D Array of (probably) Dbls, but what is the input? It is a "textured" wire, which suggests a Cluster, but of what? I don't know, as I don't see enough code to help me "figure it out for myself".
If I were you, I would mark both the post @billko provided (which helps you to figure it out for yourself) and @GerdW's as "Solutions" (you are the one who is supposed to help the Community by marking the "Solutions").
Bob Schor
06-28-2023 09:38 AM
As has been said, obviously it's an unbundle, so the original is a 1d array of clusters where each cluster contains a 2D array (SGL, or DBL, maybe CDB etc. there is no way to tell!), nothing else.
As a general rule, LabVIEW functions do not change depending on the placement, so I am confused by your qualifier "It's not inside any loop". This would not make a difference and since your image does not show any loops it is irrelevant anyway. Can you explain why you said that?
This is probably not your code, but all the blue constants could be deleted without any change in functionality.