How do I make LED turn ON and OFF based my numeric value input ? For instance, if I input 5, I would like LED to turn ON and OFF 5 times.

[GRCK5000]

So If I input 2, I would like the LED to go ON and OFF 2 times. 3 > 3 times, and so on. I tried, but failed. 

Can someone help?

See my attached code. 

[crossrulz]

When does the count get reset?  Is there supposed to be a button to start the blinking?

[GRCK5000]

Initially, the LED will be OFF.  So let's say I input number "1", I should expect the LED to turn ON then OFF once. If I input 100, I should expect the LED to turn ON and OFF 100 times. So there is no start button to start blinking. My input is the trigger basically.

Feel free to suggest too. I'm open for suggestions. 

[crossrulz · Accepted solution]

This is what I came up with.  I used the Is Value Changed.vim to detect the input changing and perform the reset.

[GRCK5000]

Thanks crossrulz!!! It works as expected. 

[paul_a_cardinale · Accepted solution]

Here's how I would do it.

[AeroSoul]

Can't see paul's idea due to VI version, but here's mine.

 

[paul_a_cardinale]

Here

[altenbach]

---

@GRCK5000 wrote:

Initially, the LED will be OFF.  So let's say I input number "1", I should expect the LED to turn ON then OFF once. If I input 100, I should expect the LED to turn ON and OFF 100 times. So there is no start button to start blinking. My input is the trigger basically.

Feel free to suggest too. I'm open for suggestions. 

---

You need to be significantly more detailed in the requirements.

• What should be the blinking rate? (should the on time be the same as the off time during blinking?
• What should happen if the number is changed while it is still blinking from the previous input? SHould the control be disabled during blinking?
• If you enter 5 and it blinks five times and then you enter 10, should it do five additional blinks or 10? What if the new number is less that the previous value?
• Why do you have a pointless feedback node instead of doing the comparison before the case structure?
• etc.

[altenbach · Accepted solution]

I don't think you need any case structures, here's one possibility: