How can I delete a specific pattern from an array

[tintin_99]

Hi,

I have a question on what is the fastest- less memory way to remove a specific pattern in a 1D array

For example in 1D U8 Array I would like to delete ( and count the number) whenever I have 3 consecutive  0xFF 

For instance :   0xFF 0x2 0x3 0xFF 0xFF 0xFF 0x2 0x3 0xFF 0xFF 0xFF  becomes 0xFF 0x2 0x3 0x2 0x3   and I had this pattern 2 times in my array

Many thanks

[cbutcher]

If you're considering only U8 arrays, I'd suggest the Search and Replace String option.

This link might also be useful: How to Convert Between Hexadecimal and ASCII in LabVIEW?

[RavensFan]

Question:  What happens if there are 4 or more in a row.

I'd just program it in a loop.  Search 1-D array for FF.  See if the next two elements are also FF.  If so, delete from array.  Search 1-D array from that point on for next FF.  Stop when you get to the end of the array.

[ben64]

You will probably have to benchmark it but array operations may be faster that converting back and forth to strings.

Ben64

[PiDi]

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@cbutcher wrote:

If you're considering only U8 arrays, I'd suggest the Search and Replace String option.

This link might also be useful: How to Convert Between Hexadecimal and ASCII in LabVIEW?

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Let's make this a bit simpler:

And I'm quite sure this is much more efficient than Bens solution (Byte Array to String and String to Byte Array are basically no-op functions).

[ben64]

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PiDi a écrit :

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And I'm quite sure this is much more efficient than Bens solution (Byte Array to String and String to Byte Array are basically no-op functions).

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Agree with you, about 4X faster.

Ben64