Counting from Iteration loop

[Gorelick]

I am currently using the iteration loop to provide a number to be used in the filename.  I need to format this number to start with 001 and continue to count  in this fashion: 002, 003, 004 etc .  But most important once I get into double digits I still need it to keep a 3 digit code so, 10 would be displayed as 010 and 11, 011.   Any help would be much appreciated!!

[pincpanter]

Use the Format into String function with format string %03d

[DavidJCrawford]

Just use Fornat Into String with %03d as your format string.

Daviid

[DavidJCrawford]

Snap! (http://en.wikipedia.org/wiki/Snap_%28game%29)

Message Edited by David Crawford on 10-20-2006 12:42 PM

[Gorelick]

Thank you for your quick response, I am still having  a problem which I am sure is very simple.  I am not sure what to put in the input 1..n connection of the  Format to String Vi connection. I am assuming this is the problem since I have put the %03d in the The format  string connector but  my number count is now 0000, 1000, 2000  rather than 000, 002,003

Thanks again for your help!!

[becktho]

It's really just that simple:

Message Edited by becktho on 10-20-2006 02:19 PM

[pincpanter]

You only need to wire the index number to input 1. Your actual outcomes have no explanation, unless you are reversing the string and concatenating a trailing '0'.
Post a picture of your code if you don't succeed.