Count up then down

[arem938]

I am trying to generate an array that counts up to 5 then back down to 1 then back up to 5. (1,2,3,4,5,4,3,2,1,2,3,4...)

I want it to be in a for loop to allow for the number of iterations to be set. I can make it work in a while loop, but I am not sure how to make it work in a for loop so the number of iterations can be set.

Thanks for your help!

[crossrulz]

What exactly do you mean by "number of iterations"? Number of points in your array?  Number of cycles (up and down is one cycle)?

[arem938]

Basically, I need the user to input a number so for example 7 would give an array of 1,2,3,4,5,4,3 - so a for loop would be needed

[arem938]

So the number of points in an array

[crossrulz · Accepted solution]

Use a shift register to keep track of if you are counting up or down.  Then use a case structure to perform whichever task is needed.

[RavensFan]

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@arem938 wrote:

I am trying to generate an array that counts up to 5 then back down to 1 then back up to 5. (1,2,3,4,5,4,3,2,1,2,3,4...)

I want it to be in a for loop to allow for the number of iterations to be set. I can make it work in a while loop, but I am not sure how to make it work in a for loop so the number of iterations can be set.

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Actually, your For Loop iteration is much closer to being correct than the while loop iteration.  The while loop version is so convoluted, I don't believe it is actually working for you.

Here is the secret.  Put in another shift register that is a boolean.  That holds the state whether you are counting up (True) or counting down (False) and drives your case structure, not your less than 5 that you have now.  Now put in one more comparison that if your value equals 5, then you put a False into the shift register.  If it equals 0, put in a True.  If it is anything else, just feed in the wire from the left shift register terminal since you don't want to change the counting direction.

Since you are counting, I would change your constants and indicators to integers rather than floating point.