06-27-2017 11:11 AM
I feel really dumb but what is negate option ? i cant find a tutorial that can help with this case
06-27-2017 11:23 AM
06-30-2017 02:46 PM
Unfortunately didn't solve my problem. it still compares the third element with first. instead of comparing second to 1st, 3rd to 2nd, 4th to 3rd..
06-30-2017 10:54 PM
07-05-2017 05:57 PM - edited 07-05-2017 05:59 PM
in your example if i wanna run the pattern twice how can i make it ? so in your example once it hit 4 , next number is again 5. so it would be 5-4=1 but instead of 1 it shows 5. I followed your pattern and once it hit the last one restarts from the beginning
07-05-2017 09:06 PM
If I understand what you're asking correctly, you can remove the "0" value outside of the loop wired to the Shift Register.
I'm not certain that's really what you want, but it'll do what you ask.
An alternative might be to index the array before starting, take the 0th element, and add it to the end (if you just want one element added) or if you want a fixed number of repeats, to nest For loops.