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LabVIEW
CLD-R Exam 1, Question 19
@Kevin_Price wrote:
Wouldn't that be 3!*2?6*4*2 = 3*2 * 2*2 * 1*2 = (3*2*1)*2 = 3!*2
Oops, nope.
6*4*2 = 48
(3!) * 2 = 12
Looks like you were applying the Distributive law to multiplication by accident....
-Kevin P
You're right, clearly i'm in the wrong, but the idea was that "decrease by 2" should be possible with factorial.
6*4*2 = 3*2 * 2*2 * 1*2 = (3*2*1)*2*2*2 = 3!*2^3 = 48 😉
Or Generalized:
x!(step n) = (x/n)!*n^x
Let's try with 12!step 3
12*9*6*3 = 1944
(12/3)!*3^4 = 4!*3^4 = 24*81 = 1944 Yay! \o/
/Y
