2D array sorting with conditions

[Jinghang]

I have a 2D array in the form as followed

1,1

1,3

2,1

2,2

2,3

3,1

4,1

4,2

5,1

5,5

I want to sort it (based on the second column) only when the element in the first column is even, for example, new array should be:

1,1

1,3

2,3

2,2

2,1

3,1

4,2

4,1

5,1

5,5

I have tried many days but failed. Thank you so much!

[RavensFan]

There are probably several different ways to attack this.

Here is the way I would try first. 

It is always a 2-D array that has just 2 columns?

Take the array and iterate through it row by row.  Build a cluster that contains the column 0 value, the column 1, value.  If yo do this with an auto-indexing For Loop, you'll wind up with a 1-D array of clusters.

Sort that 1-D array of clusters.  (one question though, it looks like your "sorted" array has the even numbers in reverse order.  That might complicate the sorting process, but there could be other ways around that.

With the Sorted 1-D array, go through element by element.  If the first item in the cluster is odd, just build the elements back into a 1-D array.  If that element is even, then take the row from the original, unsorted array.  Do that in a For Loop and you'll have a 2-D array of original odd numbers, and sorted event numbers.

[Alexander_Sobolev · Accepted solution]

Something like that I guess...

That property nodes were Array in local vars at different steps to compare side by side... Snippet breaks them =( VI is correct

[RavensFan]

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Alexander_Sobolev wrote:... Snippet breaks them =( VI is correct

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Use the Code Capture Tool you can install from VI Package Manager.  It doesn't break snippets the way the built-in VI snippet maker does.

[Jinghang]

Thank you all for the answers.

problem solved with Alexander_Sobolev's program.