1 d array selecting bits

[lfoitek]

Hello,

If i have a 1 d array of binary data, how do you selects the msb of each cell and so on down to the lsb and display each in a string format.

for example, if 1 d array looks like
1111     (0,0)
1010     (0,1)
1100     (0,2)

and then the string outputs would look like

string 1 = 111 ( msb bits)
string 2 = 101
string 3 = 110
string 4 = 100 (lsb bits)

attached is the vi that creates a 1 d array

Thank you

[jasonhill]

Well, since they are just plain ole strings, you can just get the first three "bits" using the string subset, then plug straight into a case structure to get the "string X" output.

Also, when you are inserting multiple consecutive elements, you can stretch the instert into array and input them all in one step.

Message Edited by jasonhill on 08-24-2006 03:00 PM

[lfoitek]

that works but what if the binary string was random.  would you be able to use the case statement?

[jasonhill]

Well, as long as you have eight cases.... While it might be possible to programatically generate the result string based on some rules govering the binary string, the case structure will be easier to debug and maintain. 

[Matt_W1]

I think this should work.

Message Edited by Matt W on 08-24-2006 04:15 PM

[jasonhill]

Ah, now I see.  I missunderstood the question.  You want to transpose your 2D array.  (Why the heck are you carrying your bits around in strings?  That is what U32 is for.)

Message Edited by jasonhill on 08-24-2006 05:02 PM

[lfoitek]

i don't think i want to transspose my array unless i am not understanding my problem correctly.  i want to have a 1 d array of elements with the same length of binary strings.  if the array looks like

[1111, 0000, 1010]  then there will be 4 separate output strings that look like

[101]
[100]
[101]
[100]

i guess i am just using strings for the ability of changing back and forth to hex, other data that i am working with has X's for don't cares.  i don't know if you can do that with u32 so i just went with strings.

[jasonhill]

I look at [1111, 0000, 1010] and see:

1111
0000
1010

Which, transposed would be:

101
100
101
100

Then it is just a matter of dismantling and reassembling the strings.



Note that Matt's solution is much more elegant...

Message Edited by jasonhill on 08-24-2006 05:16 PM

[lfoitek]

when i transposed the array of [ 1111, 0000, 1010] this is what labview gave.

[lfoitek]

have you tried to run your example?  this is what i was getting as the  out put.