Error in expression: Wrong data type for actual parameter

[Hartmut-Germany]

Hi everyone!

I  want to use Dasylab to collect some data from a device through a RS232 module.

There are 2 types of Intput Signal. One is started with "A" and the other one is started with "B". And I have already set these two Signals into String 1 and 2. (use fomular "A" a $1 \r) Now I want to seperate these String into different variables. An example is showed below.

string1: 861200  into Variable1: 86  Variable2: 1200

I use the Expression in the variable property setting. The formular is:  strval (substr (${STR_1} ,3 , 4) )

It works well in my simulation program. But when I write this small program with my main program, it shows some error. The screenshot ist linked to this subject. Al the setting are same. I am so confused. Can somebody help me?? I  will very appreciate that.

Best wishes,

Hartmut 

[CJ_Butler__DASYLab_Pro]

You said, in the other thread,

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Hi CJ,

I  want to use Dasylab to collect some data from a device through a RS232 module.

There are 2 types of Intput Signal. One is started with "A" and the other one is started with "B". And I have already set these two Signals into String 1 and 2. (use fomular "A" a $1 \r) Now I want to seperate these String into different variables. An example is showed below.

string1: 861200  into Variable1: 86  Variable2: 1200

Version of DASYLab is 2016 Basic

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Can you post the worksheet? Hopefully, the Global String will be saved with some data.

[Hartmut-Germany]

Sorry I can't, because the main program is not allowed to be uploaded. But I can say that the setting in the main program is exactly same as I have posted. Can you tell how to check if the Global String will be saved with some data. Thank you so much!!

[CJ_Butler__DASYLab_Pro]

If you cannot send the full program, do a print screen of the Define Global Strings dialog showing that string.

Usually, the values in the strings and variables are saved with the worksheet when you save. 

[Hartmut-Germany]

[Hartmut-Germany]

Hello CJ,

I think I have find where the problem is.

When I used StrVal (SubStr (${STR_1} ,3,4)), “STR_1” is the error.

When I used StrVal (SubStr (${STR_2} ,3,4)), “STR_2” is the error.

When I used StrVal (SubStr (${STR_3} ,1,4)), “1” is the error.

When I used StrVal (SubStr (${STR_3} ,3,2)), “2” is the error.

When I used StrVal (SubStr (${STR_3} ,3,4)), there is no error any more.

So, I think the error is 1 and 2. I cannot use these two numbers.