Conversion of Current to Temperature

[prana_k9]

Hello, 

I am getting started with LabVIEW and would appreciate some help in converting a current output(0-20 mA) from a LUMASENSE IGAR 12-LO 2 Color Pyrometer. I am receiving the output in my NI 9203 module that is attached to a NI cDAQ-9174. 

I am unsure as to how to do the conversion/scaling from current to a readable temperature in C.

Any help would be appreciated. 

Thank you. 

[crossrulz]

It would also depend on the range for the sensor.  But your conversion should be Reading*(Max-Min)/(20mA)+Min.

[prana_k9]

Hi, 

The range is between 400 and 3300 °C. 

So I'm guessing I input that equation into a formula block and I should be good to go? 

Please see attached picture. 

[crossrulz]

I avoid Express VIs as much as possible.  They tend to hide too much information and are inefficient.  For the calculation, just use the basic math nodes.

[prana_k9]

Thank you so much for the help!