Syntax Error while using FindIndex in TestStand Functions

[PalanivelThiruvenkadam]

Hi All,

I used this function long before which was working for me, but not sure what i am doing wrong not able to get my work done.

This is my scenario,

I have a Local variable  1D array of String assume (Locals.XXX)

i need to get First element value

I used the Below syntax

FindIndex(Locals.XXX,1,True)

Advice me what i am doing wrong

[CharlieRodway]

Hi Palanivel,

Is the array an array of strings?  Perhaps you should use

FindIndex(Locals.XXX,"1",True)

Regards,

[PalanivelThiruvenkadam]

I tried this but i am getting Empty value instead of 1st Index Value

FindIndex(Locals.XXX,"1",True)

[CharlieRodway]

The FindIndex function returns the index as a string, formatted as "[i][j][k]"; are you trying to use this or are you expecting a numeric index to be returned?

To get a numeric index, use the following expression:

IndexToOffset(Locals.Array, FindIndex(Locals.Array,"1",True))

Regards,

[PalanivelThiruvenkadam]

Hi Charlie

Thanks for the update,

I need the Index Value assume My Locals.Array contains values as ["asd","fgh","jkl","qwe","rty","uio"]

If my index value is 1 then i need the output as "fgh"

[CharlieRodway]

Hi Palanivel,

See the attached example.

[PalanivelThiruvenkadam]

Hi Charlie

Its Working Vice Versa i can able to retrive my index for my Index Vaue  which is same as Search 1D Array in labVIEW Functions.

My requirement is to work as same as Index array in labVIEW

[PalanivelThiruvenkadam · Accepted solution]

Thanks Charlie

I will use an alternative Method for the same requirement

Locals.MyArray[4] instead of Find Index

Kudos to your support!

[CharlieRodway]

No problem - glad I could help!