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How to measure AC current at 230V

Hi,

 

I have done a number of projects using labview in the past measuring DC voltage and current using shunt resistors and such.

 

I have a new project in an area I am not too familiar with.  I understand health and safety issues working with 230v etc, and this is not a problem.

My project involves measuring and plotting inrush current of some 230v products.  My question is thus;  How do I measure AC current using a NI USB6008?

 

Thanks in advance

 

Martin.

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Hello,

 

I would suggest trying to find a clamp meter or power quality analyzer that can measure current and output the value over serial(rs232) or GPIB, you can then use NI-VISA/GPIB to read this and bypass your USB-6008. 

 

I suggest this over using your USB-6008 for safety and ease. 

Message Edited by macaba on 08-05-2009 07:25 AM
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Hmm... While not technically impossible, measuring a 230V current source with a 10V non isolated data acquisition device sounds like a "thermal event" waiting to happen 😉  I'd strongly urge you to consider a product designed to handle such high voltages (for your own safety!).

 

That said, if you happened to have discrete points of an AC waveform (say, +/- 1V across a shunt), it is possible to convert them to an RMS value fairly quickly: http://en.wikipedia.org/wiki/Root_mean_square .  You might also look into the various RMS VIs in labview (I like the one called RMS PtByPt).  After appropriate scaling you might end up with a reasonable picture of current through your shunt.  

 

Since the 6008 is only 12bits / 10ksps, I worry that you might not get a very good reading depending on how fast your inrush is and the frequency of your source.

 

Quickie simulation using a *slowly* ramped up sine wave:

 

vshunt.JPG 

 

 

This all assumes that you're still alive after setting your system up 😉   Sometimes it's best not to leave these things to chance! NI does make high resolution, high voltage, isolated multimeters capable of current measurements that would give you a much better picture without all the hassle of math, shunts and possible electrocution 🙂   

 

Hugs,

memoryleak 

Message Edited by memoryleak on 08-05-2009 03:38 PM
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Hello,

 

If you are happy measuring upto 3A, this may be suitable

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Use a current transformer for AC. A core with one turn primary and  200 - 1000 turns secondary and a 10 to 100 Ohm resisitor.

Better units use active compensation methods with a hall sensor   LEM(.com) is a good source.

 

Both provide isolation 🙂

 

 

Greetings from Germany
Henrik

LV since v3.1

“ground” is a convenient fantasy

'˙˙˙˙uıɐƃɐ lɐıp puɐ °06 ǝuoɥd ɹnoʎ uɹnʇ ǝsɐǝld 'ʎɹɐuıƃɐɯı sı pǝlɐıp ǝʌɐɥ noʎ ɹǝqɯnu ǝɥʇ'


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