I'm not sure that what you are looking for is valid. In the standard "traditional" spectrum analyzer a narrow bandwidth variable frequency filter is swept across the band of interest, but when you are doing it digitally you basically are getting everything and then using an FFT to resolve, from the complex waveform received, the components that make up that waveform. Usually the only filtering is to limit the maximum frequency to below 1/2 of your sampling frequency to prevent aliasing (Nyquist theorem) Similarly, I'm not sure what in the FFT realm cooresponds to "video bandwidth" on your Agilent or Rhode & Schwarz Spectrum Analyzer. The width of your FFT's bins, which might be coorespondent, is related to the sample rate/sec and the total number of samples (which needs to be a power of 2), i.e. sampling at 11025 samples/sec, analyzing a sample set containing 8196 produces 11025/8196 = 1.35Hz wide bins. Now cooresponding with the sweep time on a SpecA the time needed to collect those samples would be #S* period, or #S*(1/fS) = 8196*(1/11025)= 0.743Sec. The more samples (higher resolution, narrow bin widths) the longer "the sweep".
P.M.
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Senior Test Engineer North Shore Technology, Inc.
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