03-16-2009 05:52 AM - edited 03-16-2009 05:53 AM
03-16-2009 07:23 AM
03-16-2009 07:41 AM
I think you should stick with the Single-Sided Output. I think showing frequency's above the Nyquist frequency in a spectrum plot is wrong. The information value is zero.
http://en.wikipedia.org/wiki/Nyquist_frequency
03-16-2009 07:47 AM
I am Joseph from London.
I am trying to find the answer of your question so can you send more detail of
the above question.
Joseph
03-16-2009 09:03 AM
Just to explain your problem. I am doing it because the help is pretty useless on this topic. You have a problem because your cluster order is wrong. To use a waveform graph you should built your cluster this way
1. Element=X0
2. Element=delta x(interval between elements on x axis)
3. Element=data set (data array)
Now you can place a waveform graph on your block diagram and wire it to the cluster output
More here .....\examples\general\graphs\gengraph.llb\Waveform Graph.vi
03-19-2009 01:17 PM
03-19-2009 10:40 PM
03-19-2009 10:53 PM - edited 03-19-2009 10:54 PM
03-19-2009 11:44 PM
Exactly what are you trying to do over there? You have two very odd pieces of code.
1. You take an array, split it at some index, then put it back together. What comes out is identical to what you put in.
2. What are you bundling into a cluster? You have an array, but you are also bundling in an integer 1 and a double numeric value. What are the 1 and the double supposed to mean?
Are you actually trying to build a waveform? If so, you should be using the Build Waveform function on the waveform palette.
03-20-2009 12:02 AM
I took another look at our VI and saw that your graph is actually an odd cluster of a double, integer, and double array (in that order). How did you create that? And why?
The reason your bundle cluster won't connect with it is that you bundled your cluster in the opposite order (array, integer, then double).
Reverse the order of your bundle cluster then you'll be able to connect the wire to the Real "waveform graph". But that still doesn't explain why that graph is an odd cluster.