initialize linear array

[ymormy]

What is the most efficient way to initialize an array of constant increment? I want to quickly build an array with the starting element value, increment, and number of elements all passed in to it. I know I could start with an empty array and keep resizing it and adding element in a for loop. But was told that resizing is not very efficient. Somehow I could use replace array subset. But how do you do that?

Thanks.

[mfitzsimons]

Cheers

[JeanPierre]

Use the VI "Ramp Pattern.vi"

[altenbach]

Why would you need any "array resizing"? Just use autoindexing. Since N is known from the beginning, LabVIEW can efficiently allocate the output array.

The Ramp pattern that JP mentioned is not available in "LabVIEW base" and the inputs are a bit different than your requirement (N, start, end). It is trivial to cook your own with a few strokes of the mouse. Attached is one example. (LabVIEW 7.0)

Message Edited by altenbach on 05-06-2006 11:10 AM

[ymormy]

Thank you all very much!

[habeb1987]

thank you for the information but if i need to add upper limit how can you do that

[altenbach]

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@habeb1987 wrote:

thank you for the information but if i need to add upper limit how can you do that

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This thread has not seen activity for 8 years, so the information might be a bit stale.

What do you mean by "upper limit"? Do you (1) want a specific endpoint or (2) do you want to coerce the final ramp to an upper limit where it becomes horizontal instead of increasing?

Solution for (1): Have you tried ramp pattern? the "by samples" needs [start, end, N]. "end" is your upper limit?

Solution for (2): add an "In range and coerce" function to the ramp. (words for arrays, limits can still be scalar)