Hi Ron@ld,
sure you can use this method,
please note the AC- estimate output is RMS not a real signal.
You have to get the DC component and subtract it from the input signal.
See example
Mike
"Ron@ld" wrote:
> Hi,
>
> For some close to DC frequency measurements I'm using a DC accelerometer. It
> produces a waveform around 3 volts (AC: app. 1 volt, DC app. 3 volt)
>
> Before sending this array to the power spectrum.vi I remove the DC component
> by using 'AC and DC estimator.VI'. From the signal I subtract the by this vi
> produced DC component.
>
> Can anyone think of a reason why this method is wrong??
>
> Thanx,
>
> Ron@ld
