Replace LF or CR or Both with WhiteSpace in LabVIEW

[pratik0403]

Hi,

I am facing issue while replacing string. I have one buffer which may contains multiple CR or LF or both. I just want to replace these with the white space.

I am using "search and replace.vi" for this purpose, I have changed this VI to Regular expression by right+click. In input I have given my buffer, in search string input [\r\n]$ regular expression and in replace string I have given "Empty string" constant. 

I think I have made correct changes for the issue but nothing working so far.

Thanks,

Pratik

[GerdW · Accepted solution]

Hi Praktik,

I just want to replace these with the white space.

Simple solution without regex:

[pratik0403]

Thanks for this simple solution..

[ben64]

But it still simpler with regex

Ben64