LabVIEW
Locate repeated values
Solved!
Place the value from the second column into a shift register, then compare the current and previous values. If they differ, start a new group, else append to the current group.
Here's a very simple example (LV8.5).
dan07 wrote:Using the above values as example, the located groups would be:
Group 1 (Group of 0 values) - Indexes 1,2,3
Group 2 (Group of 1 values) - Indexes 4,5,6,7
Group 3 (Group of 1 values) - Indexes 10,11,12
Group 4 (Group of 0 values) - Indexes 13,14,15,16
Group 5 (Group of 0 values) - Indexes 19,20,21,22,23
I assumed you also wanted group6 (24, 25). If you don't want this, just remove the code to the right of the FOR loop and connect the indicator directly to the shift register.
I would also recomment that you start with zero as the first index. Simply remove the "+1" to do so.
A minimal change would be to check the size of each group and retain it only if the size is sufficient.
Here's quick rewrite that only retains groups with 3 or more elements.
dan07 wrote:The index array outside the For Loop, outputs the whole array and a single element (the first element of the array). Question: the outputed element its just to start the comparasion and feed the shift register with something?
If we don't initialize the shift register, it will contain the last value from the last run if we run the VI several times in a row. The initialization might not be needed in this particular case, but I did not study it in detail. Initially, I had slightly different code inside the loop where it made an important difference. 😉
dan07 wrote:Attached there are to images with the Case Structures Highlighted by red circles. I do not know how to set up the case structure to do something when the array size is 0,1 or 2 (since that the title of the case structure its just 0, and not 0,1 or 2). And another question: how did you set up the case structure to work when the array size its equal or greater than 3? 3, 4, 5, 6, 7, 8, 9......... Because I do not know how to set the "3..." to the title of the case structure.
The case structure has two cases, the "3.." Meaning three and anything higher and "0,Default" meaning anything else. Just type "3.." to define that case. Do you have difficulty with that?
You could also deifine one case as "..2" and the other as "default". Same difference. 😄
dan07 wrote:Ok. I understood what you said. In this case the element to initializes the shift register its quite important.
dan07 wrote:The only question that I have is: You said that "0" means "anything else". But if I want three different cases, one for "0", another to "3 or greater" and another to "anything else", in this case "0" will not act as "anything else", how I should set up the cases in this situation?
No, the 0 is irrelevant here, you could even leave it out. What matters is that the case is defined as "default". Make one case "0", once case "3.." and a third case the default (right-click...make this the default case).
SImilarly...
- you could have two cases "..2" and "3.." covering all possible cases (no default needed).
- You could have 5 cases,
- default"
- "2..7"
- "20..25"
- "-100"
- 244
- and an all inputs that don't fit cases 2 through 5 will execute case 1. An input of 21 wound trigger case 3, 243 would trigger case 1 and 244 woud trigger case 5.
Anything is possible!
