How to convert string with numbers into U8 with ascii

[OnlyOne]

Hello,

i have a string with only numbers 0..9.

Now i want to convert this into an U8-array.

This works up to here but now the problem: How can i change each character into its ascii-value?

Example:

input: 123 (string)

output: x31, x32, x33 (U8-array)

Thanks for the help

[Coq_Rouge · Accepted solution]

This is very easy

String To Byte Array Function
Owning Palette: String/Array/Path Conversion Functions

Converts a string into an array of unsigned bytes. Each byte in the array has the ASCII value of the corresponding character in the string.

[Naity]

Hello OnlyOne,

There is a function doing what you want called "String to Byte Array" under "Programming>String>Conversion". It returns the ASCII code of the string as U8 (49 for x31 for example).

 

Regards (EDIT: Coq Rouge was faster)

[shjukheter]

You are right. I know that String to byte array could do that but I don't know that it gives as ASCII. Perhaps, I am doing it like this but end up with some error. 

[Coq_Rouge]

I

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@shjukheter wrote:

You are right. I know that String to byte array could do that but I don't know that it gives as ASCII. Perhaps, I am doing it like this but end up with some error. 

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Now I am somewhat lost. If you use the function we have pointed you to. You will get wat you want the string "123" will be converted to an array with 3 numbers. 49,50,51 or 0x31,0x32,0x33 in hex. Do you want an array with the numbers 1,2,3 ?

[Matthew_Kelton]

If you look at the output of the string to U8 you get 49, 50, 51 or 0x31, 0x32, 0x33.

The for loop will give you strings 1, 23, and 3 I believe (you string subset has some logical errors in it).  Since you are using the string as a hex value, you'll get 0x01, 0x23, and 0x03.