Hi,
I've built a little .vi in LV 6.1 that will decipher the average of the actual data received, i.e. if there's three items, 1.0, Nan, 2.0, then the average is 1.5. I've done it this way, rather than (1+2)/3 = 1, because if you inserted 1.5 as NaN, then it works out correctly, but if you insert 1, the average becomes 1.33333.
Hope it helps
(It's got error handling in too, just in case you manage to produce an input array that is all NaN!)
S.
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