Count a case stucture

[TapTap]

Hello all,

how I try to count how many times a case stucture is entered. I have the case sturcture inside a while loop and I use an increment together with shift registers. But when the case stucture is entered the increment is exectuted with the while loop frequency. How I can count only once each time ? 

[LV_Pro]

Instead of using the loop increment, set the shift register to 0 (zero) outside the loop, then just put an increment (a "+1"),found in the numeric palette,  in the case that you want to count.

[apok]

you're almost there....you wanted to count the #s of "true".try using bool crossing and a SR

[LV_Pro]

Ah, Apok understood your requirement a bit better I think.

[RavensFan]

Your picture doesn't show up in your original post.  It is just a box with a red X.  I don't know how you tried to insert it.  You need to sue the picture of the tree on the tool bar of the edit menu.

[TapTap]

Sorry for the picture. I'll try once again. I think the upper solutions work well. Thanks a lot for your respones.

[RavensFan]

You need to wire through in the false case.

And like Putnam said, put a zero constant to the left hand shift register so it restarts at zero.

Put a stop control going into your while loop's stop terminal.  And put a wait statement in the loop so the loop isn't greedy.