Array Interpolation

[dfaweew]

hello,everyone!I had asked a similar question in here http://forums.ni.com/t5/LabVIEW/Array-Interpolation/m-p/2819440#M825228,But now I want to know how this interpolation:In a [1] to insert a value, in a [3] to insert three values, in a [5] to insert five values , so that in turn the cycle continues until it reaches 100,I do not know how to do , hoping to get help, thank you!

[altenbach]

Just to make things clear, what you are asking has nothing to do with "interpolation" unless the element that you insert contain a proportionally interpolated value based on the neighbors.

---

@dfaweew wrote:

hello,everyone!I had asked a similar question in here http://forums.ni.com/t5/LabVIEW/Array-Interpolation/m-p/2819440#M825228,But now I want to know how this interpolation:In a [1] to insert a value, in a [3] to insert three values, in a [5] to insert five values , so that in turn the cycle continues until it reaches 100,I do not know how to do , hoping to get help, thank you!

---

You need to be much more clear in the problem description. what does "in a [1]" or "in a [3]", etc mean? Please show us a small sample array and tell us how it should look like after the various operations.

[dfaweew]

First of all thank you for your reply！I want to achieve is such as the following:left-----right!

[altenbach]

Well, this seems to be another homework.

What have you tried so far and where did you encounter problems?

[dfaweew]

sorry!I made a mistake，The following picture shows the relationship is in need of conversion；

I refer  to the VI You gave me before;I started the next test , but that the number of intervals of each insert is a fixed value，The number of insert values can not reach a situation of increasing，And I looked over all the array vi，Does not seem to help，please give me some Proposal，thank you!

[altenbach]

Again: What have you tried and where did you encounter difficulties. Show us some thought process and solution attempts and we will guide you in the right direction. This is a help forum, not a homework service.

[GerdW]

Hi dfaweew,

it seems you need to do this:

- in the 1st iteration you take one element and append one zero.

- in the 2nd iteration you take the next two elements and append two zeros…

- in the 3rd iteration you take the next three elements and append three zeros…

Did you get the scheme?

As Christian said: start to code , attach your VI and tell us, where you run into problems with it!

[dfaweew]

hello!

I 've used this vi to achieve functional ，As shown in FIG.but now i need to do this:

- in the 1st iteration you take four element and append four zero.

- in the 2nd iteration you take the next eight elements and append eight zeros…

- in the 3rd iteration you take the next sixteen elements and appendsixteen zeros….....Cycle....like show at Figure 3

I tried to achieve this by the way  in Figure 2.

But think of the shift register can not seem to realize the functions I want to achieve；and I also want to use Decimate 1D Array Function and Interleave 1D Arrays Function to achieve ,But still can not seem to find it；I now have no way；Please give me some valuable suggestions or tell me how to do，Best regards,

[altenbach]

You should be ashamed to post code pictures with hidden an right-to-left wires. Next time attach the VI instead. You are also doing this way too complicated. Try to do it with a single loop and 25% of the current code. For the second problem, you can use the same counter but scale the value with powers of two.

[dfaweew]

Thank you for your reply!you say do it with a single loop and 25% of the current code. can you Change my vi or attach your vi!It sounds easier said than done,Best regards,