LabVIEW
1d array substitute
Hi RJP,
two questions:
What kind of array (datatype)?
What kind of mark?
General algorithm:
1) do a comparison "<0" and the full array, resulting in a boolean array
2) for loop with your 1d array and the boolean array as indexing inputs: in the loop you do a replacement depending on the boolean value, autoindexing enabled for output
two questions:
What kind of array (datatype)?
What kind of mark?
General algorithm:
1) do a comparison "<0" and the full array, resulting in a boolean array
2) for loop with your 1d array and the boolean array as indexing inputs: in the loop you do a replacement depending on the boolean value, autoindexing enabled for output
Hi RJP,
so you have to convert your DBL array to a string array and do the replacements in the string array. For conversion you can use "number to fractional string"...
The example shows how to do it - but you will get memory problems with very big DBL arrays
Message Edited by GerdW on 02-15-2008 09:09 PM
so you have to convert your DBL array to a string array and do the replacements in the string array. For conversion you can use "number to fractional string"...
The example shows how to do it - but you will get memory problems with very big DBL arrays
Message Edited by GerdW on 02-15-2008 09:09 PM
You cannot do it with a waveform if you want the data as strings.
Here's one way, starting with the Y component array of the waveform....
modify as needed. 🙂
Message Edited by altenbach on 02-15-2008 12:41 PM
"number to fractional string".
Another possibility would be to keep the output DBL and just change to NaN for negative numbers.
Just wire across the false case and use a NaN DBL diagram constant in the true case..
This would be cheaper. 😉
